natural gas methane ethane

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A natural gas mixture consists of 89.4 mole percent CH4 (methane) and 10.6 mole percent C2H6 (ethane).?

Suppose water is saturated with the gas mixture at 20°C and 1.00 atm total pressure, and the gas is then expelled from the water by heating. What is the composition in mole fractions of the gas mixture that is expelled? The solubilities of CH4 and C2H6 at 20°C and 1.00 atm are 0.023 g/L H2O and 0.059 g/L H2O, respectively.

methane?
ethane?

_____Assumption: gas is composed of ONLY the two hydrocarbons dissolved in the water

mole fraction of methane = (g/l CH4 / MW CH4 g/mole) / [(g/l CH4 / MW CH4 g/mole) + (g/l C2H6 / MW g/mole)] = ??

mole fraction of C2H6 = 1.00 – mole fraction of methane = ??

Plug and SOLVE

Basic mathematics is a prerequisite to chemistry – I just try to help you with the methodology of solving the problem.

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